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5x^2-5x+2=3x^2-3x
We move all terms to the left:
5x^2-5x+2-(3x^2-3x)=0
We get rid of parentheses
5x^2-3x^2-5x+3x+2=0
We add all the numbers together, and all the variables
2x^2-2x+2=0
a = 2; b = -2; c = +2;
Δ = b2-4ac
Δ = -22-4·2·2
Δ = -12
Delta is less than zero, so there is no solution for the equation
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